2x^2=643204

Solution for 2x^2=643204 equation:

2x^2=643204

We move all terms to the left:

2x^2-(643204)=0

a = 2; b = 0; c = -643204;
Δ = b2-4ac
Δ = 02-4·2·(-643204)
Δ = 5145632
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5145632}=\sqrt{2572816*2}=\sqrt{2572816}*\sqrt{2}=1604\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-1604\sqrt{2}}{2*2}=\frac{0-1604\sqrt{2}}{4}
=-\frac{1604\sqrt{2}}{4}
=-401\sqrt{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+1604\sqrt{2}}{2*2}=\frac{0+1604\sqrt{2}}{4}
=\frac{1604\sqrt{2}}{4}
=401\sqrt{2}
$